ParseError: bad try syntax: (try next)

[oceanlee7]

(define tolerance 0.0000001)

(define (fixed-point f first-guess)
  (define (close-enough? v1 v2)
	(< (abs (- v1 v2)) tolerance))
  (define (try guess)
	(let ((next (f guess)))
	  (newline)
	  (display next)
	  (if (close-enough? next guess)
		next
		(try next))))
  (try first-guess))

I use the calysto_scheme kernel in my jupyter. The code was running ok in MIT-scheme but in scheme kernel there was something wrong. So I think there must have a bug in it.

thank you.

[dsblank]

try is a reserved word in Python. Try replacing a different word for "try".

I'll look into doing automatic re-naming underneath so this doesn't happen.