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ndiv.cpp
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140 lines (116 loc) · 2.98 KB
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/*
*
* J1K7_7
*
*/
#include <iostream>
#include <sstream>
#include <fstream>
#include <string>
#include <vector>
#include <deque>
#include <queue>
#include <stack>
#include <set>
#include <cstring>
#include <map>
#include <iomanip>
#include <algorithm>
#include <functional>
#include <utility>
#include <bitset>
#include <cmath>
#include <cstdlib>
#include <ctime>
#include <cstdio>
#include <limits>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;
typedef vector<int> vi;
typedef vector<long long> vll;
#define l(x) (x << 1) + 1
#define r(x) (x << 1) + 2
#define mid(l, r) ((l + r) >> 1)
#define mp make_pair
#define pb push_back
#define all(a) a.begin(),a.end()
#define pr(n) printf("%d",n)
#define s(n) scanf("%d",&n)
#define debug(x) {cerr <<#x<<" = " <<x<<"\n"; }
#define debug2(x, y) {cerr <<#x<<" = " <<x<<", "<<#y <<" = " <<y <<"\n";}
#define ss second
#define ff first
#define m0(x) memset(x,0,sizeof(x))
#define snuke(c,itr) for(__typeof((c).begin()) itr=(c).begin();itr!=(c).end();itr++)
const int mod=1e9+7;
const ll mx_ll = numeric_limits<ll> :: max();
const int mx_int = numeric_limits<int> :: max();
const long double PI = (long double)(3.1415926535897932384626433832795);
inline bool ispow2(int x){return (x!=0 && (x&(x-1))==0);} //0 or 1
int msb(unsigned x){ union { double a; int b[2]; }; a = x; return (b[1] >> 20) - 1023; }
template<class T>
inline void cinarr(T a, int n){ for (int i=0;i<n;++i) cin >> a[i];}
inline ll powmod(ll a,ll b) {ll res = 1; while(b){if(b&1) res = (res*a)%mod;a = (a*a)%mod;b >>= 1;}return res;}
inline ll gcd(ll a,ll b){ll t;while(b){a=a%b;t=a;a=b;b=t;}return a;}
inline ll lcm(ll a,ll b){return a/gcd(a,b)*b;}
inline int nextint(){ int x; scanf("%d",&x); return x; }
inline ll nextll(){ ll x; scanf("%lld",&x); return x; }
const int maxN = 1e6+7;
int pp[maxN+1];
vector <int> prime;
inline void pre_sieve()
{
// there are 1007 primes < 8000
// there are 78499 primes < 1e6+7
for(ll i = 2; i < maxN; i++ )
if( pp[i] == 0 )
for(ll j = i*i; j < maxN; j += i)
pp[j] = 1;
for(int i =2; i< maxN; i++)
if(pp[i] == 0)
prime.push_back(i);
}
int main()
{
ios_base::sync_with_stdio(false); cin.tie(0);
ll a , b ; int n ;
a = nextll();
b = nextll();
n = nextint();
pre_sieve();
ll cnt = 0 ;
ll wt = 0;
for(ll i = a ; i <= b ; i++)
{
ll ndiv = 1;
ll num = i;
for(auto pr : prime )
{
if ( pr * pr > num ) break;
if ( num % pr == 0 )
{
wt = 0;
while ( num % pr == 0 )
{
wt++;
num /= pr;
}
ndiv *= (wt + 1 );
}
}
if ( num > 1 )
{
ndiv *= ( 2 ) ;
}
if ( ndiv == n )
{
cnt++;
}
}
printf("%lld\n",cnt);
return 0;
}