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95-GenerateTrees.py
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81 lines (69 loc) · 2.42 KB
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# Python3
from typing import List
# Definition for a binary tree node.
class TreeNode:
def __init__(self, val=0, left=None, right=None):
self.val = val
self.left = left
self.right = right
class Solution:
def generateTrees(self, n: int) -> List[TreeNode]:
def generateTrees(start, end):
if start > end:
return [None,]
allTrees = []
for i in range(start, end + 1): # 枚举可行根节点
leftTrees = generateTrees(start, i - 1)
rightTrees = generateTrees(i + 1, end)
for left in leftTrees:
for right in rightTrees:
currTree = TreeNode(i)
currTree.left = left
currTree.right = right
allTrees.append(currTree)
return allTrees
return generateTrees(1, n) if n else []
# C++
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
vector<TreeNode*> generateTrees(int start, int end) {
if (start > end) {
return { nullptr };
}
vector<TreeNode*> allTrees;
// 枚举可行根节点
for (int i = start; i <= end; i++) {
// 获得所有可行的左子树集合
vector<TreeNode*> leftTrees = generateTrees(start, i - 1);
// 获得所有可行的右子树集合
vector<TreeNode*> rightTrees = generateTrees(i + 1, end);
// 从左子树集合中选出一棵左子树,从右子树集合中选出一棵右子树,拼接到根节点上
for (auto& left : leftTrees) {
for (auto& right : rightTrees) {
TreeNode* currTree = new TreeNode(i);
currTree->left = left;
currTree->right = right;
allTrees.emplace_back(currTree);
}
}
}
return allTrees;
}
vector<TreeNode*> generateTrees(int n) {
if (!n) {
return {};
}
return generateTrees(1, n);
}
};