Result.Try with async lambda returning Result<T>

[LaXiS96]

Hello,
I am trying to use Result.Try with an async lambda based on the non-async example in the README, somewhat like this:

Result<Guid> result = await Result.Try(async Task<Result<Guid>> () => {
    await Task.Delay(100);
    return Result.Ok(new Guid());
});

but Result.Try returns a Result<Result<Guid>> which is not what I expected.

Could this case be handled by adding an overload like this?

Task<Result<T>> Result.Try<T>(Func<Task<Result<T>>> action, ...)

Or is there a recommended way to handle this differently?

Thank you

[SoufianeByt]

Same issue