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44 lines (43 loc) · 1.26 KB
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/**
* 3761. Minimum Absolute Distance Between Mirror Pairs
*
* mirror pair = indices(i,j)
* reverse(nums[i] === nums[j]) 若數字前面為0,則省略0
* 回傳最小mirror pair絕對距離 abs(i - j),若無,回傳-1
*
* @param {number[]} nums
* @return {number}
*/
var minMirrorPairDistance = function(nums) {
/**
* 陣列元素兩個為一組(i,j),每個元素反轉後跟下一個元素比較是否一致。若一致 abs(index i - index j),取最小結果
*/
// 反轉數字
function reverseNum(x){
let y = 0;
while(x > 0){
y = y * 10 + (x % 10);
x = Math.floor(x / 10);
}
return y;
}
let map = new Map();
let ans = nums.length + 1;
for(let i = 0;i < nums.length;i++){
if(map.has(nums[i])){
ans = Math.min(ans,i - map.get(nums[i]));
}
map.set(reverseNum(nums[i]),i);
}
return ans === nums.length + 1 ? -1 : ans;
};
let nums = [12,21,45,33,54]
/*
Output: 1
Explanation:
The mirror pairs are:
(0, 1) since reverse(nums[0]) = reverse(12) = 21 = nums[1], giving an absolute distance abs(0 - 1) = 1.
(2, 4) since reverse(nums[2]) = reverse(45) = 54 = nums[4], giving an absolute distance abs(2 - 4) = 2.
The minimum absolute distance among all pairs is 1.
*/
console.log(minMirrorPairDistance(nums));