Business days

[m-aciek]

Would it make sense to extend the syntax with business days support? It would need to operate in a context of a concrete business days calendar.

iter = croniter('2 4 * * b', base)  # 04:02 on every business day
iter = croniter('0 0 * * b#1,b#2', base)  # 1st business day, and 2nd business day of the month
iter = croniter('0 0 * * b#3,Lb', base)  # 3rd and last business day of the month

The part that would be practical and doesn't have an expression (is it possible to compose it in?) is first/last/n-th business day in a week. Maybe for that we could use a second symbol e.g. bw meaning “business day in a week”?

iter = croniter('2 4 * * bw', base)  # 04:02 on every business day
iter = croniter('0 0 * * bw#1,bw#2', base)  # 1st business day, and 2nd business day of the week
iter = croniter('0 0 * * bw#3,Lbw', base)  # 3rd and last business day of the week

[potiuk]

The problem is that there is no "business day" - or rather business days depend not only on country but on many political decisions - and not only on country level, but often regional, or even "per organisation" - what is "business" for you might often be "non-business" for me. There is really no way to make a "universal" approach other than the user supplying actual calendar of what is and what is not business day.

I'd say that logic of that should be handled externally to croniter. Like launching something on every potentially business day in your case and checking if this is really a business day (and which) in your organisation.

[potiuk]

But if you can come up with a concrete idea an contribute it (for example how to provide a custom calendar) - yeah - such contribution might be accepted (however for now I will convert it to a discussion).