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ActivityStack的findTaskLocked方法功能描述有误 #23

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@WalterLsaacson

原文是:
findTaskLocked():该函数的功能是找到目标ActivityRecord(target)所在的任务栈(TaskRecord),如果找到,则返回栈顶的ActivityRecord,否则,返回null
通过查看源码发现这里匹配的是Taskrecord的栈底ActivityRecord,返回的是栈顶ActivityRecord.
希望能交流一下这个点。

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