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hasPathSum.cpp
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39 lines (39 loc) · 1.02 KB
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/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
int sum = 0, target = 0;
bool dfs(TreeNode* root) {
if (!root->left && !root->right) {
return sum + root->val == target;
}
sum += root->val;
bool ifleft = root->left ? dfs(root->left) : false;
if (ifleft) {
return true;
}
bool ifright = root->right ? dfs(root->right) : false;
if (ifright) {
return true;
}
sum -= root->val;
return false;
}
bool hasPathSum(TreeNode* root, int targetSum) {
if (!root) {
return false;
}
target = targetSum;
sum = 0;
return dfs(root);
}
};