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JS Adagrams
Major Learning Goals/Code Review
| Criteria | yes/no, and optionally any details/lines of code to reference |
|---|---|
Correctly uses variables, and only uses const and let variables. The program prefers const variables. The program never uses var. |
✔️ |
| Practices best-practices in JavaScript syntax. There are semi-colons at the end of most lines that need semi-colons. Variables and functions are named with camelCase. | ✔️ |
| Correctly creates and calls functions within an object with proper syntax (parameters, return statements, etc.) | ✔️ |
| Uses correct syntax for conditional logic and iteration | ✔️ |
| Practices git with at least 3 small commits and meaningful commit messages | ✔️ |
Utilizes unit tests to verify code; tests can run using the command $ npm test test/adagrams.test.js and we see test successes and/or failures |
✔️ |
Functional Requirements
| Functional Requirement | yes/no |
|---|---|
For the drawLetters function, there is an appropriate data structure to store the letter distribution. (You are more likely to draw an 'E' than an 'X'.) |
✔️ |
Utilizes unit tests to verify code; all tests for drawLetters and usesAvailableLetters pass |
✔️ |
Utilizes unit tests to verify code; all tests for scoreWord pass |
✔️ |
Utilizes unit tests to verify code; all tests for highestScoreFrom pass |
✔️ |
Overall Feedback
Great work on this project! In this project you’ve taken some interesting logic and worked it into JavaScript syntax. Your code is clever and logical. Nice work!
| Overall Feedback | Criteria | yes/no |
|---|---|---|
| Green (Meets/Exceeds Standards) | 5+ in Code Review && 3+ in Functional Requirements | ✔️ |
Code Style Bonus Awards
Was the code particularly impressive in code style for any of these reasons (or more...?)
| Quality | Yes? |
|---|---|
| Perfect Indentation | ✅ |
| Elegant/Clever | ✅ |
| Concise | ✅ |
| Logical/Organized | ✅ |
| @@ -1,7 +1,107 @@ | |||
| const letterPool = { | |||
| A: [9, 1], | |||
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I like how you stored the frequency and scores together to DRY up your code.
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| usesAvailableLetters(word, hand = drawLetters()) { | ||
| // if letter is found in hand, the search continues at an incremented index. this way a letter in hand cant be counted twice | ||
| return word.toUpperCase().split('').every(( index => letter => index = hand.indexOf(letter, index) + 1)(0)); |
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Wow. This is a lot on one line. Looks slick, but at the same time, consider splitting up this logic to enhance readability.
Comment on lines
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| for (const word of tiedWords) { | ||
| if (word.length === 10) { | ||
| winningIndex = tiedWords.indexOf(word); | ||
| highestScore = {score: scores[indices[winningIndex]], word: tiedWords[winningIndex]}; | ||
| return highestScore; | ||
| } else { | ||
| if (word.length < shortest.length) { | ||
| shortest = word; | ||
| shortestIndex = tiedWords.indexOf(shortest); | ||
| } | ||
| } |
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Consider breaking out this logic into a helper method such as tieBreaker
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Assignment Submission: JS Adagrams
Congratulations! You're submitting your assignment. Please reflect on the assignment with these questions.
Reflection