Issue 2 : Implémentation de la methode reduce()#22
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HumbertMeyers
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Oct 25, 2019
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| this.numerator = numerator; | ||
| this.denominator = denominator; | ||
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| try { | ||
| if(denominator != 0) { | ||
| double answer = numerator / denominator; | ||
| System.out.println(answer); | ||
| } | ||
| } catch (Exception e) { | ||
| System.out.println("Denominator can't be 0"); | ||
| } | ||
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ceci est un test pour la methode reduce(). Si possible ne pas prendre en compte cette modification
Retrait du code de test
Non pris en compte
vvandenschrieck
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Oct 25, 2019
vvandenschrieck
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vvandenschrieck
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Algorithme à revoir!
| */ | ||
| private void reduce() { | ||
| if(this.numerator % this.denominator == 0) { | ||
| Fraction(this.numerator, this.denominator); |
Collaborator
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Cette ligne ne fait rien!
| if(this.numerator % this.denominator == 0) { | ||
| Fraction(this.numerator, this.denominator); | ||
| }else { | ||
| int gcd = Fraction(this.denominator, this.numerator % this.denominator); |
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Comment est-ce qu'un appel de constructeur pourrait renvoyer un int? Et pourquoi faire un appel de constructeur?
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