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| "Return the number of total permutations of the provided string that don't have repeated consecutive letters. Assume that all characters in the provided string are each unique.", | ||
| "For example, <code>aab</code> should return 2 because it has 6 total permutations (<code>aab</code>, <code>aab</code>, <code>aba</code>, <code>aba</code>, <code>baa</code>, <code>baa</code>), but only 2 of them (<code>aba</code> and <code>aba</code>) don't have the same letter (in this case <code>a</code>) repeating.", | ||
| "Remember to use <a href='http://forum.freecodecamp.org/t/how-to-get-help-when-you-are-stuck/19514' target='_blank'>Read-Search-Ask</a> if you get stuck. Try to pair program. Write your own code." | ||
| "把一个字符串中的字符重新排列生成新的字符串，返回新生成的字符串里没有连续重复字符的字符串个数。连续重复只以单个字符为准。", |
| "Remember to use <a href='http://forum.freecodecamp.org/t/how-to-get-help-when-you-are-stuck/19514' target='_blank'>Read-Search-Ask</a> if you get stuck. Try to pair program. Write your own code." | ||
| "把一个字符串中的字符重新排列生成新的字符串，返回新生成的字符串里没有连续重复字符的字符串个数。连续重复只以单个字符为准。", | ||
| "例如：<code>aab</code>应该返回 2， 因为它总共有 6 种排列方式： <code>aab</code>， <code>aab</code>， <code>aba</code>， <code>aba</code>， <code>baa</code>， <code>baa</code>，但是其中只有 2 个没有连续重复的字符（ 字符 a 是本例中的重复字符 ）：<code>aba</code>，<code>aba</code>", | ||
| "如果你遇到了困难，请点击 <a href='http://forum.freecodecamp.org/t/how-to-get-help-when-you-are-stuck/19514'target='_blank'> 帮助 </a>。你可以找人” 结对编程 “，但不要因此放弃思考。" |
| "Compare and update the inventory stored in a 2D array against a second 2D array of a fresh delivery. Update the current existing inventory item quantities (in <code>arr1</code>). If an item cannot be found, add the new item and quantity into the inventory array. The returned inventory array should be in alphabetical order by item.", | ||
| "Remember to use <a href='http://forum.freecodecamp.org/t/how-to-get-help-when-you-are-stuck/19514' target='_blank'>Read-Search-Ask</a> if you get stuck. Try to pair program. Write your own code." | ||
| "创建一个<a href='https://baike.baidu.com/item/%E4%BA%8C%E7%BB%B4%E6%95%B0%E7%BB%84' target='_blank'>二维数组</a>，比较并更新存储在<code>二维数组</code>中的 ”库存“ 元素，然后并将其与新产生的第二个二维数组进行对比，更新当前的 ”库存“ 项的数量（<code>arr1</code>），如果找不到这个对比对象，那么将新的对象和数量添加到 “库存” 数组中。注意：返回的 “库存” 数组应该是按照数组元素的首字母顺序排序", | ||
| "如果你遇到了困难，请点击<a href='http://forum.freecodecamp.org/t/how-to-get-help-when-you-are-stuck/19514' target='_blank'>帮助</a>。你可以找人“结对编程“，但不要因此放弃思考。", |
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August 8, 2018 17:10
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… translate) Merge Request: functional-programming.json complete Created By: @黄雨纯 Accepted By: @黄雨纯 URL: https://freecodecamp.coding.net/p/challenges/git/merge/10
…ramming -> translate) Merge Request: Revert "functional-programming.json complete" Created By: @胡落阳 Accepted By: @柳星 URL: https://freecodecamp.coding.net/p/challenges/git/merge/11
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