Create resolved_lab_subqueries.sql

resolved_lab_subqueries.sql

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+
+SELECT 
+    COUNT(i.inventory_id) AS number_of_copies
+FROM 
+    film f
+LEFT JOIN 
+    sakila.inventory i ON f.film_id = i.film_id
+WHERE 
+    f.title = 'Hunchback Impossible';
+
+SELECT 
+    title, 
+    length
+FROM 
+ film
+WHERE 
+    length > (SELECT AVG(length) FROM film)
+ORDER BY 
+    length DESC;
+
+SELECT 
+    first_name, 
+    last_name
+FROM 
+   actor
+WHERE 
+    actor_id IN (
+        SELECT 
+            actor_id
+        FROM 
+          film_actor
+        WHERE 
+            film_id IN (
+                SELECT 
+                    film_id
+                FROM 
+                  film
+                WHERE 
+                    title = 'Alone Trip'
+            )
+    );
+
+    SELECT 
+    f.film_id,
+    f.title AS film_title,
+    c.name AS category_name
+FROM film f
+JOIN film_category fc ON f.film_id = fc.film_id
+JOIN category c ON fc.category_id = c.category_id
+WHERE c.name = 'Family'
+ORDER BY f.title ASC;
+
+SELECT 
+    co.country,
+    cu.first_name,
+    cu.last_name,
+    cu.email
+FROM customer cu
+JOIN address a ON cu.address_id = a.address_id
+JOIN city ci ON a.city_id = ci.city_id
+JOIN country co ON ci.country_id = co.country_id
+WHERE co.country = 'Canada'
+ORDER BY cu.last_name ASC;
+
+SELECT 
+    first_name,
+    last_name,
+    email
+FROM customer
+WHERE address_id IN (
+    SELECT address_id 
+    FROM address 
+    WHERE city_id IN (
+        SELECT city_id 
+        FROM city 
+        WHERE country_id = (
+            SELECT country_id 
+            FROM country 
+            WHERE country = 'Canada'
+        )
+    )
+);
+
+SELECT 
+    f.film_id,
+    f.title AS film_title
+FROM film f
+JOIN film_actor fa ON f.film_id = fa.film_id
+WHERE fa.actor_id = (
+    -- Subconsulta: Encuentra el ID del actor más prolífico
+    SELECT actor_id
+    FROM film_actor
+    GROUP BY actor_id
+    ORDER BY COUNT(film_id) DESC
+    LIMIT 1
+)
+ORDER BY f.title ASC;
+
+SELECT DISTINCT
+    f.title AS film_title
+FROM film f
+JOIN inventory i ON f.film_id = i.film_id
+JOIN rental r ON i.inventory_id = r.inventory_id
+WHERE r.customer_id = (
+    -- Subconsulta: Encuentra el ID del cliente con mayor gasto acumulado
+    SELECT customer_id
+    FROM payment
+    GROUP BY customer_id
+    ORDER BY SUM(amount) DESC
+    LIMIT 1
+)
+ORDER BY f.title ASC;
+
+SELECT 
+    customer_id AS client_id,
+    SUM(amount) AS total_amount_spent
+FROM payment
+GROUP BY customer_id
+HAVING SUM(amount) > (
+    -- Subconsulta: Calcula el promedio de lo que ha gastado cada cliente
+    SELECT AVG(total_por_cliente)
+    FROM (
+        SELECT SUM(amount) AS total_por_cliente
+        FROM payment
+        GROUP BY customer_id
+    ) AS subquery_promedio
+)
+ORDER BY total_amount_spent DESC;
+
+
+