Solution with 56 Bytes#8
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roland-schmitz wants to merge 10 commits into
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Amazing. Saving you one more byte.
- 65 -> 64 - added contributor names
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This 56 byte solution Is by far not as readable as Svens solution. The reduce and the idea with the prime factors are from Udos solution. But I choose a different approach:
The reduce starts with 1 and is multiplied with 2 for numbers >= 25 and multiplied with 2 and 3 (=6) for numbers >= 30.
The reduce falls back to 1 if a number is smaller than 25 and 0 is not reached already.
If the reduce is once divisible by 864 which is 22222 * 333 it becomes 0 and does not change its value any more and true is returned.
864 can be interpreted as contains a sequence with 5 numbers >= 25 and at least 3 of them are >= 30.
Includes some improvements from Mathis Müller.